2.08 g of chromium combines with 0.96 g of oxygen to form an oxide of chromium.
Determine the formula of this oxide of chromium and use it to complete the balanced equation.
Relative atomic masses (ArA_rAr): Cr=52.0\text{Cr} = 52.0Cr=52.0, O=16.0\text{O} = 16.0O=16.0
You must show your working.
Balanced equation for the reaction:
..... Cr+..... O2→..... \text{..... Cr} + \text{..... O}_2 \rightarrow \text{.....} ..... Cr+..... O2→.....