A hydrocarbon, CxHy\text{C}_x\text{H}_yCxHy, is burned completely in excess oxygen, forming 17.6 g of carbon dioxide and 9.0 g of water.
The relative formula mass (MrM_rMr) of the hydrocarbon is 58.
Calculate the molecular formula of the hydrocarbon CxHy\text{C}_x\text{H}_yCxHy.
(Relative atomic masses, ArA_rAr: H=1.0\text{H} = 1.0H=1.0, C=12\text{C} = 12C=12; relative formula masses, MrM_rMr: H2O=18\text{H}_2\text{O} = 18H2O=18, CO2=44\text{CO}_2 = 44CO2=44)
258 exam-style questions on Edexcel GCSE Chemistry Calculations involving masses. Each one has a worked solution and a mark scheme showing where the marks go.