A strip of aluminium foil has a mass of 5.4 g. Use Ar(Al)=27A_r(\mathrm{Al}) = 27Ar(Al)=27 and the Avogadro constant 6.02 × 1023 mol-1. How many aluminium atoms does the strip contain?
3.25×10243.25 \times 10^{24}3.25×1024 aluminium atoms
3.32×10−253.32 \times 10^{-25}3.32×10−25 aluminium atoms
1.20×10231.20 \times 10^{23}1.20×1023 aluminium atoms
3.01×10243.01 \times 10^{24}3.01×1024 aluminium atoms
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.