An open crucible containing 2.50 g of calcium carbonate has a total mass of 46.25 g. A student heats the crucible until all the calcium carbonate has decomposed. No solid is lost, and the carbon dioxide escapes.
CaCO3(s)→CaO(s)+CO2(g)\mathrm{CaCO_3(s)} \rightarrow \mathrm{CaO(s)} + \mathrm{CO_2(g)}CaCO3(s)→CaO(s)+CO2(g)
Relative atomic masses: C=12\mathrm{C} = 12C=12, O=16\mathrm{O} = 16O=16, Ca=40\mathrm{Ca} = 40Ca=40.
What balance reading should the student record when the decomposition is complete and the crucible has cooled?
43.75 g43.75\,\mathrm{g}43.75g
46.25 g46.25\,\mathrm{g}46.25g
45.15 g45.15\,\mathrm{g}45.15g
44.85 g44.85\,\mathrm{g}44.85g
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.