A heavy paraffin molecule, W, is thermally cracked in a refinery to produce one molecule of hexane, C6H14C_6H_{14}C6H14, and one molecule of an alkene, Z.
W→C6H14+Z W \rightarrow C_6H_{14} + Z W→C6H14+ZThe relative formula mass (MrM_rMr) of Z is 112. The empirical formula of Z is CH2CH_2CH2.
Deduce the molecular formula of the reactant paraffin W.
Show your working.
(Relative atomic masses: H=1.0H = 1.0H=1.0, C=12.0C = 12.0C=12.0)
258 exam-style questions on Edexcel GCSE Chemistry Calculations involving masses. Each one has a worked solution and a mark scheme showing where the marks go.