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Question 59

The formula of ammonium phosphate is $(NH4)3PO4(\text{NH}_4)_3\text{PO}_4$ .

Calculate the total number of atoms that combine to form 4.47 g of ammonium phosphate.

Give your answer to 3 significant figures.

Relative atomic masses ( $A_r$ ): $H=1.0\text{H} = 1.0$ , $N=14.0\text{N} = 14.0$ , $O=16.0\text{O} = 16.0$ , $P=31.0\text{P} = 31.0$

Avogadro constant = 6.02 × 10²³ per mole

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Calculations involving masses Questions

GCSE
Chemistry
Calculations involving masses

258 exam-style questions on Edexcel GCSE Chemistry Calculations involving masses. Each one has a worked solution and a mark scheme showing where the marks go.

Calculations involving masses

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Calculations involving masses

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Question 59

The formula of ammonium phosphate is $(NH4)3PO4(\text{NH}_4)_3\text{PO}_4$ .

Calculate the total number of atoms that combine to form 4.47 g of ammonium phosphate.

Give your answer to 3 significant figures.

Relative atomic masses ( $A_r$ ): $H=1.0\text{H} = 1.0$ , $N=14.0\text{N} = 14.0$ , $O=16.0\text{O} = 16.0$ , $P=31.0\text{P} = 31.0$

Avogadro constant = 6.02 × 10²³ per mole

[4]

Markscheme

Calculations involving masses Questions

GCSE
Chemistry
Calculations involving masses

258 exam-style questions on Edexcel GCSE Chemistry Calculations involving masses. Each one has a worked solution and a mark scheme showing where the marks go.