A technician makes a sodium chloride solution for a class practical. The technician dissolves 12.5 g of sodium chloride in water and makes the volume of the solution up to 250 cm3\mathrm{cm^{3}}cm3.
Name the piece of apparatus the technician uses to measure the mass of sodium chloride.
Convert 250 cm3\mathrm{cm^{3}}cm3 into dm3\mathrm{dm^{3}}dm3.
Calculate the concentration of the sodium chloride solution in g dm−3\mathrm{g\,dm^{-3}}gdm−3. Use the equation: concentration (g dm−3)=mass of solute (g)volume of solution (dm3)\displaystyle \text{concentration }(\mathrm{g\,dm^{-3}}) = \frac{\text{mass of solute (g)}}{\text{volume of solution }(\mathrm{dm^{3}})}concentration (gdm−3)=volume of solution (dm3)mass of solute (g)
A sports drink contains glucose at a concentration of 13.5 g dm−3\mathrm{g\,dm^{-3}}gdm−3. Calculate the mass of glucose in 0.500 dm3\mathrm{dm^{3}}dm3 of the sports drink. Use the equation: mass of solute (g)=concentration (g dm−3)×volume of solution (dm3)\text{mass of solute (g)} = \text{concentration }(\mathrm{g\,dm^{-3}}) \times \text{volume of solution }(\mathrm{dm^{3}})mass of solute (g)=concentration (gdm−3)×volume of solution (dm3)
The technician adds more water to the sodium chloride solution. State what happens to the concentration of the solution.
55 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.