Calculate the total number of atoms in 0.45 moles0.45\text{ moles}0.45 moles of butane, C4H10\text{C}_4\text{H}_{10}C4H10.
Avogadro constant=6.02×1023 mol−1\text{Avogadro constant} = 6.02 \times 10^{23}\text{ mol}^{-1}Avogadro constant=6.02×1023 mol−1
258 exam-style questions on Edexcel GCSE Chemistry Calculations involving masses. Each one has a worked solution and a mark scheme showing where the marks go.