When copper reacts with bromine, copper bromide is formed.
Two possible equations for this reaction are:
A 2Cu+Br2→2CuBr2\text{Cu} + \text{Br}_2 \rightarrow 2\text{CuBr}2Cu+Br2→2CuBr B Cu+Br2→CuBr2\text{Cu} + \text{Br}_2 \rightarrow \text{CuBr}_2Cu+Br2→CuBr2
In an experiment, 12.70 g of copper reacts completely with bromine to form 44.70 g of copper bromide.
Show, using a calculation, which reaction, A or B, is taking place.
You must show your working.
(Relative atomic masses, ArA_rAr: Br=80.0\text{Br} = 80.0Br=80.0; Cu=63.5\text{Cu} = 63.5Cu=63.5)
