A student reacts 9.0 g of aluminium completely with oxygen. The reaction is represented by 4Al+3O2→2Al2O34\mathrm{Al} + 3\mathrm{O_{2}} \rightarrow 2\mathrm{Al_{2}O_{3}}4Al+3O2→2Al2O3. Use Al=27\mathrm{Al} = 27Al=27 and O=16\mathrm{O} = 16O=16.
Which mass of oxygen is required for all the aluminium to react?
8.0 g
4.0 g
16.0 g
12.0 g
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.