/Images/705129-equation-sheet-physics-a.pdf","initialIndex":79,"initialQuestionWindow":[{"id":"94a7499b-e029-4cf8-9e76-593d9a0a5da9","revisionId":"defe46bd-3447-4640-8746-3dae65e90cd2","questionNumber":null,"questionType":"LA","specification":"","difficulty":3,"difficultyBand":"medium","totalMarks":4,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"f850094a-7923-4646-b965-39b7556f3dc0","label":null,"content":"An industrial electric arc furnace used in steel recycling operates at a potential difference of \$650\\text{ V}\$. During a melting cycle, a total charge of \$55\\,000\\text{ C}\$ flows through the furnace.\n\nCalculate the energy transferred. Use the equation:\n\n\\\\[\\text{Charge} = \\text{Energy} \\div \\text{Potential difference}\\\\]\n\nRecord your answer to **2 significant figures**.","markscheme":"- Rearranges the formula to make energy the subject: $\\text{Energy} = \\text{Charge} \\times \\text{Potential difference}$ M1\n- Substitutes the values into the formula: $55\\,000 \\times 650$ M1\n- Calculates the exact energy as $35\\,750\\,000 \\text{ J}$ A1\n- Rounds to 2 significant figures to obtain $36\\,000\\,000 \\text{ J}$ (or $3.6 \\times 10^7 \\text{ J}$) A1","marks":4,"order":0,"markingRubric":null,"explanation":{"methods":[{"id":"rearrange_and_calculate","label":"Rearrange then calculate","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"\\text{Charge}=\\frac{\\text{Energy}}{\\text{Potential difference}}"},{"latex":"\\text{Energy}=\\text{Charge}\\times\\text{Potential difference}"}]},"order":1,"title":"Make energy the subject","description":"Multiply both sides by potential difference, then write energy alone. This earns the rearrangement M1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"E = Q \\times V"},{"latex":"E = \\htmlData{anchor=charge-value}{55\\,000} \\times \\htmlData{anchor=voltage-value}{650}"}],"highlights":[{"color":"amber","style":"box","anchor":"charge-value"},{"color":"amber","style":"box","anchor":"voltage-value"}]},"order":2,"title":"Substitute the values","description":"Substitute the charge and potential difference. Writing this substitution earns the second M1, even before completing the multiplication."},{"type":"hyper_latex","block":{"nodes":[{"latex":"E = 55\\,000 \\times 650"},{"latex":"E = 35\\,750\\,000\\ \\text{J}"}]},"order":3,"title":"Calculate the exact energy","description":"Multiply the two values. This exact calculation earns the A1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"E = 35\\,750\\,000\\ \\text{J}"},{"latex":"E = 36\\,000\\,000\\ \\text{J}"}]},"order":4,"title":"Round to 2 significant figures","description":"The exact value is 35 750 000 J. The third significant figure is 7, so the second significant figure rounds up. This earns the final A1."}]}],"generatedAt":"2026-07-22T11:44:59.695Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null},{"id":"9c1e0d4a-2184-484f-ab2f-36f2f366149f","revisionId":"4b1c5ca7-ca2b-4ec1-b847-00c189aeaa74","questionNumber":null,"questionType":"LA","specification":"","difficulty":4,"difficultyBand":"medium","totalMarks":4,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"51ed673d-4109-443f-82ff-71ff5a309c3a","label":null,"content":"A charge of $32\\,000\\text{ C}$ flows through an electric oven. The potential difference is $230\\text{ V}$. Calculate the energy transferred. Use the equation:\n\n$$\\text{Charge} = \\text{Energy} \\div \\text{Potential difference}$$\n\nRecord your answer to **2 significant figures**.","markscheme":"- Rearranges the formula to make energy the subject: $\\text{Energy} = \\text{Charge} \\times \\text{Potential difference}$ M1\n- Substitutes the given values: $32\\,000 \\times 230$ M1\n- Calculates the exact energy as $7\\,360\\,000\\text{ J}$ A1\n- Rounds to 2 significant figures to obtain $7\\,400\\,000\\text{ J}$ A1","marks":4,"order":0,"markingRubri

Simple circuits

Question 36

Simple circuits Questions

Simple circuits

Question 36

Simple circuits Questions