A commercial electric deep-fryer is used in a restaurant kitchen to heat cooking oil.
The deep-fryer is plugged into the mains supply and turned on. Explain why the temperature of the oil increases. Write about energy stores in your answer.
The temperature of the oil increases from 20∘C20^\circ\text{C}20∘C to 180∘C180^\circ\text{C}180∘C. The mass of the oil is 4.0 kg4.0\text{ kg}4.0 kg. The specific heat capacity of the oil is 2100 J/kg∘C2100\text{ J/kg}^\circ\text{C}2100 J/kg∘C.
Calculate the energy required to increase the temperature of the oil. Use the equation:
change in thermal energy=mass×specific heat capacity×change in temperature \text{change in thermal energy} = \text{mass} \times \text{specific heat capacity} \times \text{change in temperature} change in thermal energy=mass×specific heat capacity×change in temperatureThe power of the deep-fryer is 3000 W3000\text{ W}3000 W. The potential difference of the mains supply is 240 V240\text{ V}240 V.
Calculate the current in the heating element of the deep-fryer. Use the equation:
power=potential difference×current \text{power} = \text{potential difference} \times \text{current} power=potential difference×currentA chef suggests, 'We should use a heating element designed to draw a higher current.' Suggest two reasons why this is a good idea.
The deep-fryer has an outer casing made of stainless steel (metal).
Which wire(s) should be connected in the electric plug of the deep-fryer? Select all that apply: