Simple circuits

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Question 31
Medium

A student sets up an electrical circuit as shown in the diagram.

A schematic diagram of an electrical circuit. At the top, there is a 9.0 V battery. The circuit is a single loop. From the battery, the wire goes down to the left, passes through a resistor on the bottom-left wire, and then continues to a lamp on the bottom-right wire. There is a switch connected in parallel across the lamp, shown in an open position.

The resistor has a resistance of 12.0 Ω12.0\ \Omega12.0 Ω and the lamp has a resistance of 6.0 Ω6.0\ \Omega6.0 Ω, so that the total resistance in the circuit when the switch is open is 18.0 Ω18.0\ \Omega18.0 Ω.

a.

Calculate the current in the circuit when the switch is open.

Current = _________________ A

[3]
b.

State the potential difference across the resistor when the switch is open.

Potential difference = _________________ V

[1]
c.

The switch is now closed.

Describe how the current through the resistor changes. Explain your answer.

[2]
d.

Describe how the potential difference across the resistor changes. Explain your answer.

[2]
e.

State the potential difference across the lamp when the switch is closed.

Potential difference = _________________ V

[1]

Simple circuits Questions

  1. GCSE
  2. /Physics
  3. /Simple circuits