An electric heater is connected to the 230 V mains supply. The power of the heater is 920 W.
Use the equation: power=potential difference×current\text{power} = \text{potential difference} \times \text{current}power=potential difference×current
What is the current in the heater?
4.0 A4.0\ \text{A}4.0 A
0.25 A0.25\ \text{A}0.25 A
690 A690\ \text{A}690 A
1150 A1150\ \text{A}1150 A
42 exam-style questions on OCR GCSE Physics 3.2 Simple circuits, covering 3.2.1 Series and parallel circuits, 3.2.2 Circuit symbols and circuit diagrams, 3.2.3 Current, potential difference and resistance, 3.2.4 Ohm's law, 3.2.5 Ohmic and non-ohmic resistors, 3.2.6 Designing circuits to investigate resistance, 3.2.7 Linear and non-linear circuit components, 3.2.8 Current-potential difference graphs for components, 3.2.9 Resistance in series and parallel, 3.2.10 Series and parallel circuit problems, 3.2.11 Circuits for measurement and testing, 3.2.12 Power transfer in circuit devices, and 3.2.13 Energy and power in resistor circuits. Each one has a worked solution and a mark scheme showing where the marks go.