laces.\n\nThat inconsistency is the second mistake and earns **B1**.","highlights":[{"text":"| 4.0 | 0.800 |","location":"specification"}]},{"type":"text","order":3,"title":"Correct the current reading","content":"Record every current reading to two decimal places. Therefore change\n\n$$0.800\\ \\mathrm{A}\\text{ to }0.80\\ \\mathrm{A}$$\n\nThe value has not changed; only its recorded precision has. This correction earns the final **B1**, giving all $4$ marks."}]}],"generatedAt":"2026-07-22T12:11:30.952Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"a621ecf6-f844-4578-8d84-8a5f997ab3f4","label":"c","content":"Use the equation:\n\n\\[\\text{potential difference} = \\text{current} \\times \\text{resistance}\\]\n\nto calculate the resistance of the heating coil when the potential difference is \$6.0\\text{ V}\$.","markscheme":"- Rearranges the equation to $R = \\frac{V}{I}$ and substitutes $V = 6.0\\text{ V}$ and $I = 1.00\\text{ A}$ M1\n- Obtains $R = 6.0\\ \\Omega$ (or ohms) A1","marks":2,"order":2,"markingRubric":null,"explanation":{"methods":[{"id":"rearrange_substitute","label":"Rearrange and substitute","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"V = I\\htmlData{anchor=resistance-factor}{R}"},{"latex":"\\htmlData{anchor=resistance-subject}{R} = \\frac{V}{I}"}],"connections":[{"to":"resistance-subject","from":"resistance-factor","color":"sky","label":"divide by I"}]},"order":1,"title":"Rearrange the equation","description":"Keep the potential difference term, then divide both sides by the current so resistance is the subject."},{"type":"hyper_latex","block":{"nodes":[{"latex":"R = \\frac{\\htmlData{anchor=fraction}{6.0\\,\\mathrm{V}}}{1.00\\,\\mathrm{A}}"},{"latex":"R = \\htmlData{anchor=answer}{6.0\\,\\Omega}"}],"highlights":[{"color":"green","style":"box","anchor":"answer"}],"connections":[{"to":"answer","from":"fraction","color":"orange","label":"evaluate: 6.0 V ÷ 1.00 A"}]},"order":2,"title":"Substitute the values","description":"Use the ammeter reading I = 1.00 A carried forward from the earlier part, together with V = 6.0 V. The rearrangement and substitution together earn the M1 mark; evaluating the quotient and giving the answer with its unit earns A1."}]}],"generatedAt":"2026-07-22T11:14:24.581Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"3635b571-ff53-46b7-89c3-d79c6a300da2","label":"d","content":"### (b) Graph and Relationships\n\nDescribe the relationship between current and potential difference for the heating coil shown by the data in the table.","markscheme":"- Describes that as potential difference increases, the current increases at a decreasing rate B1","marks":1,"order":3,"markingRubric":null,"explanation":{"methods":[{"id":"read_the_table_trend","label":"Read the table trend","steps":[{"type":"text","order":0,"title":"Compare the increases","content":"Look down the table as potential difference rises. The current still rises, but each further increase in current is smaller than the previous one: it is increasing at a decreasing rate.\n\nWrite: **As potential difference increases, current increases at a decreasing rate.** This is the complete statement for **B1**.","highlights":[{"text":"Describe the relationship between current and potential difference for the heating coil shown by the data in the table.","location":"specification"}]}]}],"generatedAt":"2026-07-22T12:13:41.918Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"db25e12a-b591-4f93-be91-d6c3345268ea","label":"e","content":"Explain how the student could adapt the experiment to investigate the resistance of a fixed resistor rather than a heating coil.","markscheme":"- Explains that the student should replace the heating coil with a fixed resistor B1\n- Explains that they should adjust the variable resistor/rheostat (or change the power supply voltage) to record a new set of current and potential difference readings B1

Simple circuits

Question 34

Simple circuits Questions

Simple circuits

Question 34

Simple circuits Questions