A student investigates the electrical properties of a filament lamp and records his measurements in a table:
| Potential difference (V) | Current (A) |
|---|---|
| 0.0 | 0.0 |
| 3.0 | 1.8 |
| 6.0 | 3.0 |
| 9.0 | 3.8 |
Calculate the power dissipated by the filament lamp when the potential difference is 6.0 V.
Use the equation: power=potential difference×current\text{power} = \text{potential difference} \times \text{current}power=potential difference×current
Calculate the energy transferred if the filament lamp is operated at this potential difference (6.0 V) for 4 minutes.
Use the equation: energy transferred=power×time\text{energy transferred} = \text{power} \times \text{time}energy transferred=power×time
42 exam-style questions on OCR GCSE Physics Simple circuits. Each one has a worked solution and a mark scheme showing where the marks go.