One molecule of hexadecane, C16H34\text{C}_{16}\text{H}_{34}C16H34, is cracked to produce three molecules of propene, C3H6\text{C}_3\text{H}_6C3H6, and one molecule of product X.
C16H34→3C3H6+product X \text{C}_{16}\text{H}_{34} \rightarrow 3\text{C}_3\text{H}_6 + \text{product X} C16H34→3C3H6+product XWhat is the molecular formula of product X?
C7H14\text{C}_7\text{H}_{14}C7H14
C10H22\text{C}_{10}\text{H}_{22}C10H22
C7H16\text{C}_7\text{H}_{16}C7H16
C13H28\text{C}_{13}\text{H}_{28}C13H28
Practise Edexcel GCSE Chemistry Fuels with exam-style questions for Foundation and Higher tier. 100 questions, matched to the Edexcel GCSE Chemistry (1CH0) specification and written in Paper 1 and Paper 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.