One molecule of dodecane, C12H26\text{C}_{12}\text{H}_{26}C12H26, is cracked to produce two molecules of ethene, C2H4\text{C}_2\text{H}_4C2H4, and one molecule of product Y.
C12H26→2C2H4+product Y \text{C}_{12}\text{H}_{26} \rightarrow 2\text{C}_2\text{H}_4 + \text{product Y} C12H26→2C2H4+product YWhat is the formula of product Y?
C8H16\text{C}_8\text{H}_{16}C8H16
C8H18\text{C}_8\text{H}_{18}C8H18
C10H22\text{C}_{10}\text{H}_{22}C10H22
C10H18\text{C}_{10}\text{H}_{18}C10H18
Practise Edexcel GCSE Chemistry Fuels with exam-style questions for Foundation and Higher tier. 100 questions, matched to the Edexcel GCSE Chemistry (1CH0) specification and written in Paper 1 and Paper 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.