One molecule of dodecane, C12H26\text{C}_{12}\text{H}_{26}C12H26, is cracked to produce two molecules of ethene, C2H4\text{C}_2\text{H}_4C2H4, and one molecule of product Y.
C12H26→2C2H4+product Y \text{C}_{12}\text{H}_{26} \rightarrow 2\text{C}_2\text{H}_4 + \text{product Y} C12H26→2C2H4+product YWhat is the formula of product Y?
C8H16\text{C}_8\text{H}_{16}C8H16
C8H18\text{C}_8\text{H}_{18}C8H18
C10H22\text{C}_{10}\text{H}_{22}C10H22
C10H18\text{C}_{10}\text{H}_{18}C10H18
130 exam-style questions on Edexcel GCSE Chemistry 9.1 Fuels, covering 9.1.1 Hydrocarbons and crude oil, 9.1.2 Fractional distillation of crude oil and its fractions, 9.1.3 The alkanes as a homologous series, 9.1.4 Complete and incomplete combustion, 9.1.5 Pollutants from burning fuels, 9.1.6 Hydrogen as a fuel and non-renewable fossil fuels, and 9.1.7 Cracking of larger alkanes. Each one has a worked solution and a mark scheme showing where the marks go.