A marine salvage ROV (Remotely Operated Vehicle) of mass 2.5 kg is operating at depth. Its motion is governed by two horizontal thruster forces P1\mathbf{P}_1P1 and P2\mathbf{P}_2P2 such that:
P1=(3a−11) N and P2=(52b) N \mathbf{P}_1 = \begin{pmatrix} 3a \\ -11 \end{pmatrix} \text{ N and } \mathbf{P}_2 = \begin{pmatrix} 5 \\ 2b \end{pmatrix} \text{ N} P1=(3a−11) N and P2=(52b) Nwhere a a\,a and b b\,b are constant parameters. The resulting acceleration of the ROV is observed to be a=(2ba−1) m s−2\mathbf{a} = \begin{pmatrix} 2b \\ a - 1 \end{pmatrix} \text{ m s}^{-2}a=(2ba−1) m s−2.
Determine the value of a a\,a and the value of bbb.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.