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Further Kinematics

Further Kinematics

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Question 191

A particle P P\,P moves with constant acceleration of 2i−3j2\mathbf{i} - 3\mathbf{j}2i−3j ms−2^{-2}−2. At time t=0t = 0t=0, the particle is at the origin, OOO, and moving with a velocity of 2i−2j2\mathbf{i} - 2\mathbf{j}2i−2j ms−1^{-1}−1

a.

Find the velocity of P P\,P at time t=2t = 2t=2 seconds

[2]
b.

Find the speed of P P\,P at time t=2t = 2t=2 seconds

[2]
c.

Show that the position vector of P P\,P at time t=2t = 2t=2 seconds is 8i−10j8\mathbf{i} - 10\mathbf{j}8i−10j m

[3]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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