A particle P P\,P moves in a straight line with constant velocity. Initially P P\,P is at the point A A\,A with position vector (3i−4j) m(3\mathbf{i} - 4\mathbf{j}) \text{ m}(3i−4j) m. At time t=2t = 2t=2, P P\,P is at the point B B\,B with position vector (−3i+8j) m(-3\mathbf{i} + 8\mathbf{j}) \text{ m}(−3i+8j) m.
The displacement from A A\,A to B B\,B is (−612)\begin{pmatrix} -6 \\ 12 \end{pmatrix}(−612). Find the velocity of PPP.
When t=5t = 5t=5 P P\,P is at the point CCC. Find the distance ACACAC.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.