A boat B B\,B moves with a constant velocity. At noon, B B\,B is at the point with position vector (4i−6j) km(4\mathbf{i} - 6\mathbf{j}) \text{ km}(4i−6j) km with respect to a fixed origin OOO. At 1430 the boat is at the point with position vector (−11i+14j) km(-11\mathbf{i} + 14\mathbf{j}) \text{ km}(−11i+14j) km.
Find the time, in hours, between noon and 1430.
Hence find the velocity of BBB.
Find the bearing of the velocity vector
Find an expression, in terms of ttt, for the position of BBB t t\,t hours after noon.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.