A particle P P\,P moves in a straight line with constant velocity. Initially P P\,P is at the point A A\,A with position vector (4i−3j) m(4\mathbf{i} - 3\mathbf{j}) \text{ m}(4i−3j) m. At time t=3t = 3t=3, P P\,P is at the point B B\,B with position vector (−5i+9j) m(-5\mathbf{i} + 9\mathbf{j}) \text{ m}(−5i+9j) m.
Show that the velocity of P P\,P is −3i+4j-3\mathbf{i} + 4\mathbf{j}−3i+4j.
When t=5t = 5t=5 P P\,P is at the point CCC. Verify that the distance AC AC\,AC is 25 m.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.