A boat B B\,B moves with a constant velocity. At noon, B B\,B is at the point with position vector (2i−5j) km(2\mathbf{i} - 5\mathbf{j}) \text{ km}(2i−5j) km with respect to a fixed origin OOO. At 1430 the boat is at the point with position vector (−8i+10j) km(-8\mathbf{i} + 10\mathbf{j}) \text{ km}(−8i+10j) km.
Find the velocity of B B\,B and hence find the bearing of the velocity vector.
Find an expression, in terms of ttt, for the position of BBB t t\,t hours after noon.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.