Skip to content

Course home

Further Kinematics

Further Kinematics

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328
Question 138

At time t t\,t seconds, where t≥0t \geq 0t≥0, a particle P P\,P moves so that its acceleration a ms−2\mathbf{a} \text{ ms}^{-2}a ms−2 is given by a=(2−2t)i+(4−t2)j\mathbf{a} = (2 - 2t)\mathbf{i} + (4 - t^2)\mathbf{j}a=(2−2t)i+(4−t2)j. At the instant when t=0t = 0t=0, the velocity of P P\,P is 24i ms−124\mathbf{i} \text{ ms}^{-1}24i ms−1

a.

Find the velocity of P P\,P when t=4t = 4t=4

[3]
b.

Find the value of t t\,t at the instant when P P\,P is moving in a direction perpendicular to i\mathbf{i}i

[3]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank