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Further Kinematics

Further Kinematics

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Question 43

A particle P P\,P has acceleration [(6t2−8)i+(4t2+8t)j] ms−2[(6t^2 - 8)\mathbf{i} + (4t^2 + 8t)\mathbf{j}] \text{ ms}^{-2}[(6t2−8)i+(4t2+8t)j] ms−2 where t t\,t is the time in seconds. When t=3t = 3t=3 the velocity of the particle is (30i+40j) ms−1(30\mathbf{i} + 40\mathbf{j}) \text{ ms}^{-1}(30i+40j) ms−1

a.

Find an expression for the velocity of P P\,P in terms of ttt

[4]
b.

Initially the particle is at the point with position vector (3i−6j)(3\mathbf{i} - 6\mathbf{j})(3i−6j). Find an expression for the displacement of P P\,P in terms of ttt

[4]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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