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Further Kinematics

Further Kinematics

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Question 231

After t t\,t seconds, a particle has position vector r=[(4t2+2t−4)i+(t2+20t)j] m\mathbf{r} = [(4t^2 + 2t - 4)\mathbf{i} + (t^2 + 20t)\mathbf{j}] \text{ m}r=[(4t2+2t−4)i+(t2+20t)j] m

a.

Find the time at which the particle is travelling on a bearing of 045∘045^\circ045∘

[4]
b.

Find the magnitude of the acceleration of the particle.

[4]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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