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Further Kinematics

Further Kinematics

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Question 316

A particle moves in a straight line relative to an origin OOO. The displacement, sss metres, of the particle from OOO at time ttt seconds is given by

s=p+5t−ke−0.4t s = p + 5t - ke^{-0.4t} s=p+5t−ke−0.4t

where ppp and kkk are constants. At time t=2t = 2t=2, the acceleration of the particle is −2.4 m s−2-2.4\text{ m s}^{-2}−2.4 m s−2.

a.

Show that k≈33.4k \approx 33.4k≈33.4

[4]
b.

Given that the particle has an initial displacement of 8 metres, find the value of ppp. Give your answer to two significant figures.

[2]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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