A particle P P\,P has acceleration [(3t2−4)i+(2t2+4t)j] ms−2[(3t^2 - 4)\mathbf{i} + (2t^2 + 4t)\mathbf{j}] \text{ ms}^{-2}[(3t2−4)i+(2t2+4t)j] ms−2 where t t\,t is the time in seconds. When t=3t = 3t=3 the velocity of the particle is (15i+36j) ms−1(15\mathbf{i} + 36\mathbf{j}) \text{ ms}^{-1}(15i+36j) ms−1
Find an expression for the velocity of P P\,P in terms of ttt
Initially the particle is at the point with position vector (0i+0j)(0\mathbf{i} + 0\mathbf{j})(0i+0j). Find an expression for the displacement of P P\,P in terms of ttt
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.