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Further Kinematics

Further Kinematics

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Question 220

At time t t\,t seconds, where t≥0t \geq 0t≥0, a particle P P\,P moves so that its position vector r m\mathbf{r} \text{ m}r m is given by r=(t2−4t)i+5tj\mathbf{r} = (t^2 - 4t)\mathbf{i} + 5t\mathbf{j}r=(t2−4t)i+5tj.

Find, giving your answer in exact form, the value of t t\,t at the instant when the speed of P P\,P is 13ms-1

[5]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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