A small object starts with an initial velocity u=(−8i+2j) ms−1\mathbf{u} = (-8\mathbf{i} + 2\mathbf{j}) \text{ ms}^{-1}u=(−8i+2j) ms−1. It accelerates at a constant rate in the direction (i+j)(\mathbf{i} + \mathbf{j})(i+j). Given that the magnitude of the acceleration is 52 ms−25\sqrt{2} \text{ ms}^{-2}52 ms−2,
Show that the velocity vector v\mathbf{v}v after t t\,t seconds is given by v=[(5t−8)i+(5t+2)j] ms−1\mathbf{v} = [(5t - 8)\mathbf{i} + (5t + 2)\mathbf{j}] \text{ ms}^{-1}v=[(5t−8)i+(5t+2)j] ms−1.
Using your answer to part (a), or otherwise, find the value of t t\,t for which the speed of the particle is at its minimum.
Practise Edexcel A Level Maths Further Kinematics with exam-style questions for A Level Maths. 54 questions covering Vectors in Kinematics, Vector Methods with Projectiles, Variable Acceleration in One Dimension, Differentiating Vectors, and Integrating Vectors, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.