A particle P P\,P moves with constant acceleration 6i−4j6\mathbf{i} - 4\mathbf{j}6i−4j ms−2^{-2}−2. When t=0t = 0t=0, the particle is at point A A\,A and moving with a velocity −19i+4j-19\mathbf{i} + 4\mathbf{j}−19i+4j ms−1^{-1}−1. At time t=Tt = Tt=T the particle is moving in the direction of vector (5i−12j)(5\mathbf{i} - 12\mathbf{j})(5i−12j)
Find the value of TTT.
At time t=2t = 2t=2 seconds, P P\,P is at the point BBB. Find the distance ABABAB.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.