A student investigates how temperature affects catalase from liver.
She adds the same mass of liver to hydrogen peroxide at each temperature. She records the volume of oxygen collected during the first 40 seconds of each reaction.
| Temperature in ∘C^\circ\text{C}∘C | Volume of oxygen collected in 40 seconds in cm3\text{cm}^3cm3 |
|---|---|
| 20 | 16 |
| 30 | 28 |
| 40 | 36 |
| 50 | 10 |
| 60 | 2 |
Use the equation
rate=volume of oxygentime\text{rate} = \dfrac{\text{volume of oxygen}}{\text{time}}rate=timevolume of oxygen
Calculate the missing value in the partly completed working for 20 ∘C20\ ^\circ\text{C}20 ∘C.
rate=1640=‾ cm3s−1\text{rate} = \dfrac{16}{40} = \underline{\hspace{1.5cm}}\ \text{cm}^3\text{s}^{-1}rate=4016= cm3s−1
State the temperature at which the activity of catalase was highest.
Explain why the activity of catalase increased between 20 ∘C20\ ^\circ\text{C}20 ∘C and 40 ∘C40\ ^\circ\text{C}40 ∘C.
184 exam-style questions on OCR GCSE Biology 1.2 What happens in cells (and what do cells need)?, covering 1.2.1 Structure of DNA, 1.2.2 Nucleotides and complementary bases, 1.2.3 Protein synthesis, 1.2.4 DNA structure and the proteins made, 1.2.5 Investigating enzymatic reactions, and 1.2.6 Mechanism of enzyme action. Each one has a worked solution and a mark scheme showing where the marks go.