A treatment process uses an enzyme to break down substance X in wastewater. The reaction produces a gas.
A scientist mixes a fixed volume and concentration of the enzyme with different concentrations of substance X. The scientist records the volume of gas produced in 40 s.
The temperature, pH and total volume of the reaction mixture are kept constant.
| Concentration of substance X in %\%% | Volume of gas produced in 40 s in cm3\mathrm{cm^3}cm3 |
|---|---|
| 0.5 | 8 |
| 1.0 | 15 |
| 2.0 | 24 |
| 4.0 | 28 |
| 8.0 | 28 |
Calculate the rate of gas production at a concentration of 8.0% of substance X.
Give your answer in cm3 s−1\mathrm{cm^3\,s^{-1}}cm3s−1.
Explain the pattern in the results as the concentration of substance X increases from 0.5% to 8.0%.
The scientist repeats the test using 8.0% substance X but doubles the concentration of the enzyme. Substance X remains in excess.
Predict how the volume of gas produced in 40 s will compare with 28 cm3. Explain your answer.
184 exam-style questions on OCR GCSE Biology 1.2 What happens in cells (and what do cells need)?, covering 1.2.1 Structure of DNA, 1.2.2 Nucleotides and complementary bases, 1.2.3 Protein synthesis, 1.2.4 DNA structure and the proteins made, 1.2.5 Investigating enzymatic reactions, and 1.2.6 Mechanism of enzyme action. Each one has a worked solution and a mark scheme showing where the marks go.