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Reversible reactions and equilibria

Reversible reactions and equilibria

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Question 13

Dinitrogen tetroxide (N2O4\text{N}_2\text{O}_4N2​O4​) is a colourless gas.

Nitrogen dioxide (NO2\text{NO}_2NO2​) is a brown gas.

These gases can exist together in dynamic equilibrium according to the equation:

N2O4(g)⇌2NO2(g)ΔH=+58 kJ/mol \text{N}_2\text{O}_4(\text{g}) \rightleftharpoons 2\text{NO}_2(\text{g}) \quad \Delta H = +58\text{ kJ/mol} N2​O4​(g)⇌2NO2​(g)ΔH=+58 kJ/mol

A mixture of these gases is allowed to reach equilibrium in a sealed container of fixed volume at 20∘C20^\circ\text{C}20∘C. This equilibrium mixture is pale brown in colour.

a.

The sealed container is heated to 90∘C90^\circ\text{C}90∘C.

As the temperature of the gas mixture increases, the pressure of the gas mixture also increases.

Predict the effect of the increase in temperature on the position of equilibrium.

[1]
b.

Predict the effect of the increase in pressure on the position of equilibrium.

[1]
c.

Suggest why it is difficult to predict which way the equilibrium will shift.

[1]
d.

Suggest why the equilibrium mixture is a darker shade of brown at 90∘C90^\circ\text{C}90∘C than the equilibrium mixture at 20∘C20^\circ\text{C}20∘C.

[2]
Markscheme

Reversible reactions and equilibria Questions

  1. IGCSE
  2. /Chemistry
  3. /Reversible reactions and equilibria

28 exam-style questions on Edexcel IGCSE Chemistry Reversible reactions and equilibria. Each one has a worked solution and a mark scheme showing where the marks go.

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