A student heats 5.00 g of calcium carbonate in an open crucible.
CaCO3(s)→CaO(s)+CO2(g)\mathrm{CaCO_{3}(s) \rightarrow CaO(s) + CO_{2}(g)}CaCO3(s)→CaO(s)+CO2(g)
After cooling, the solid in the crucible has a mass of 3.40 g. Relative formula masses: CaCO3=100\mathrm{CaCO_{3}} = 100CaCO3=100, CaO=56\mathrm{CaO} = 56CaO=56.
Which conclusion is best supported by these results?
All the carbonate decomposed, giving off 1.60 g1.60\,\mathrm{g}1.60g of carbon dioxide
Some of the calcium oxide escaped from the crucible as a gas
The solid gained mass by reacting with oxygen from the air
Some of the calcium carbonate had not decomposed when weighed
55 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.