In a manufacturing trial, tungsten(VI) oxide reacts with hydrogen according to the equation
WO3+3H2→W+3H2O\mathrm{WO_3 + 3H_2 \rightarrow W + 3H_2O}WO3+3H2→W+3H2O
The masses of reactants used are shown in the table.
| Reactant | Mass in g\mathrm{g}g |
|---|---|
| WO3\mathrm{WO_3}WO3 | 23.2 |
| H2\mathrm{H_2}H2 | 0.800 |
The relative atomic masses are shown in the table.
| Element | W\mathrm{W}W | O\mathrm{O}O | H\mathrm{H}H |
|---|---|---|---|
| Relative atomic mass | 184 | 16 | 1 |
Calculate the maximum mass of tungsten that can form.
Show your working.
Calculate the mass of the reactant that remains after the reaction is complete.
142 exam-style questions on Edexcel GCSE Chemistry 2.6 Calculations involving masses, covering 2.6.1 Relative formula mass and percentage composition, 2.6.2 Empirical and molecular formulae, 2.6.3 Conservation of mass, 2.6.4 Reacting masses and concentration in g dm⁻³, 2.6.5 The mole and the Avogadro constant, and 2.6.6 Limiting reactants and stoichiometry. Each one has a worked solution and a mark scheme showing where the marks go.