Sodium hydroxide reacts with dilute nitric acid to form sodium nitrate and water.
sodium hydroxide+nitric acid→sodium nitrate+water \text{sodium hydroxide} + \text{nitric acid} \rightarrow \text{sodium nitrate} + \text{water} sodium hydroxide+nitric acid→sodium nitrate+waterA student carried out a titration to find the exact volume of dilute nitric acid that reacted with 25.0 cm3 of sodium hydroxide solution.
There were five steps in the titration, but they are not listed in the correct order.
Step P: Use a volumetric pipette to measure 25.0 cm3 of the sodium hydroxide solution.
Step Q: Transfer the sodium hydroxide solution into a clean conical flask and add a few drops of methyl orange indicator.
Step R: Fill a burette with the dilute nitric acid and record the initial reading.
Step S: Run the dilute nitric acid from the burette into the conical flask, swirling continuously, until the indicator changes colour.
Step T: Record the final reading from the burette and calculate the volume of dilute nitric acid added.
Write the steps in the correct order.
Some of the steps have been completed for you.
| R | T | |||
| --- | --- | --- | --- | --- |
276 exam-style questions on Edexcel GCSE Chemistry 4.1 Acids, covering 4.1.1 Acids, alkalis and the pH scale, 4.1.2 Hydrogen ion concentration and pH, 4.1.3 Dilute and concentrated, weak and strong acids, 4.1.4 Bases, alkalis and the reactions of acids, 4.1.5 Chemical tests for hydrogen and carbon dioxide, 4.1.6 Neutralisation as a reaction of acids with bases, 4.1.7 Preparing soluble salts, and 4.1.8 Solubility rules and preparing insoluble salts. Each one has a worked solution and a mark scheme showing where the marks go.