A student stretches a metal spring that obeys Hooke's Law. The spring constant of the spring is 45 N/m.
Calculate the force exerted by the spring when it is extended by 0.20 m. Use the equation: force=spring constant×extension\text{force} = \text{spring constant} \times \text{extension}force=spring constant×extension.
Calculate the elastic potential energy stored in the spring when it is extended by 0.20 m. Use the equation: energy=12×spring constant×extension2\displaystyle \text{energy} = \frac{1}{2} \times \text{spring constant} \times \text{extension}^2energy=21×spring constant×extension2.
39 exam-style questions on OCR GCSE Physics Forces in action. Each one has a worked solution and a mark scheme showing where the marks go.