.ocr.org.uk/Images/705129-equation-sheet-physics-a.pdf","initialIndex":27,"initialQuestionWindow":[{"id":"3e7768aa-e504-47e2-80b8-93058259ab21","revisionId":"40b0665e-9c32-49f7-af1e-a88756800b89","questionNumber":null,"questionType":"LA","specification":"","difficulty":5,"difficultyBand":"medium","totalMarks":8,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"87f4e6b2-e756-416f-91cd-03313a57ac1e","label":"a","content":"A construction worker uses a heavy-duty steel pry bar to lift a heavy concrete slab.\n\n![Steel pry bar resting on a pivot to lift a concrete slab](https://assets.mathsgenie.co.uk/aqa-qb/d61fa92f-1a5a-4384-84d6-4faf1b9af48a.png)\n\nExplain why the downward effort force needed to lift the concrete slab is **less** than the upward load force acting on the slab.","markscheme":"- Explains that the distance from the pivot to the effort force ($1.8\\text{ m}$) is much greater than the distance from the pivot to the load ($0.15\\text{ m}$) B1\n- States that a smaller force is therefore needed to produce the same moment about the pivot to achieve equilibrium B1","marks":2,"order":0,"markingRubric":null,"explanation":{"methods":[{"id":"moments","label":"Compare the moments","steps":[{"type":"text","order":0,"title":"Compare the lever arms","content":"The downward effort force acts at a distance of $1.8\\text{ m}$ from the pivot, which is much greater than the $0.15\\text{ m}$ distance for the load. For equilibrium, the moments about the pivot must be equal. Because moment depends on force multiplied by perpendicular distance, the longer effort lever arm means a smaller force produces the same moment, so the downward effort force is **less** than the upward load force.","highlights":[{"text":"**less**","location":"specification"}]}]}],"generatedAt":"2026-07-22T11:14:53.554Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"f8aec1e9-345d-416a-ba0b-170c2e156bab","label":"b","content":"The effort force applied by the worker is \$140\\text{ N}\$.\n\nCalculate the load force exerted on the concrete slab.","markscheme":"- Uses the principle of moments: $140 \\times 1.8 = F_{\\text{load}} \\times 0.15$ M1\n- Obtains $F_{\\text{load}} = 1680\\text{ N}$ A1","marks":2,"order":1,"markingRubric":null,"explanation":{"methods":[{"id":"moments","label":"Apply the principle of moments","steps":[{"type":"text","order":0,"title":"Identify the pivot","content":"Use the **principle of moments**: for a balanced lever, the clockwise turning effect equals the anticlockwise turning effect. A moment is a force multiplied by its perpendicular distance from the pivot.\n\nHere the worker's effort acts $1.8\\text{ m}$ from the pivot, while the slab (the load) acts $0.15\\text{ m}$ from it. The load force is the unknown, $F_{\\text{load}}$."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=balance}{\\color{@sky}{140\\ \\mathrm{N}\\times1.8\\ \\mathrm{m}}}=F_{\\mathrm{load}}\\times0.15\\ \\mathrm{m}"},{"latex":"F_{\\mathrm{load}}=\\htmlData{anchor=fraction}{\\dfrac{140\\ \\mathrm{N}\\times1.8\\ \\mathrm{m}}{0.15\\ \\mathrm{m}}}"},{"latex":"F_{\\mathrm{load}}=\\htmlData{anchor=answer}{\\color{@green}{1680\\ \\mathrm{N}}}"}]},"order":1,"title":"Equate the moments","description":"Set the worker's moment equal to the slab's moment. This equation earns the method mark (M1). Obtaining F_load = 1680 N earns the answer mark (A1)."}]}],"generatedAt":"2026-07-21T17:52:03.209Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"6c509da4-09b3-4145-93a5-8bd7ec252d71","label":"c","content":"A technician places a heavy car battery on a flat horizontal workbench.\n\nDescribe the **two** forces in the interaction (action-reaction) pair between the battery and the workbench.","markscheme":"- Describes Force 1: The downward force (contact force/push) exerted by the battery on the workbench B1\n- Describes Force 2: The upward normal contact force exerted by the workbench on the battery

Forces in action

Question 19

Forces in action Questions

Forces in action

Question 19

Forces in action Questions