A high-precision calibration spring inside an astronomical seismometer obeys Hooke’s Law. The spring constant of this spring is 160 N/m160\text{ N/m}160 N/m.
Calculate the magnitude of the force exerted by the spring when it is extended by 0.15 m0.15\text{ m}0.15 m from its natural length. Use the equation: force=spring constant×extension\text{force} = \text{spring constant} \times \text{extension}force=spring constant×extension.
Calculate the elastic potential energy stored in the spring at this extension. Use the equation: energy=12×spring constant×extension2\text{energy} = \frac{1}{2} \times \text{spring constant} \times \text{extension}^2energy=21×spring constant×extension2.
39 exam-style questions on OCR GCSE Physics Forces in action. Each one has a worked solution and a mark scheme showing where the marks go.