1.3 Transport in cells

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Question 19
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The rate of diffusion of a solute across a cell membrane can be modelled using Fick's Law:

Rate of diffusion∝Surface Area×Concentration DifferenceThickness of Membrane \text{Rate of diffusion} \propto \frac{\text{Surface Area} \times \text{Concentration Difference}}{\text{Thickness of Membrane}} Rate of diffusion∝Thickness of MembraneSurface Area×Concentration Difference​

A student compares diffusion in two spherical model cells, as shown in the diagram:

Comparison of diffusion into two model cells of radius r and 2r

Both cells are exposed to the same external solute concentration difference, and both have identical membrane thicknesses.

If the radius of the model cell is doubled from r r\,r to 2r2r2r, how does the initial rate of diffusion per unit volume of the cell change?

It is halved (multiplied by a factor of 0.50.50.5)

It is quartered (multiplied by a factor of 0.250.250.25)

It is doubled (multiplied by a factor of 2.02.02.0)

It is quadrupled (multiplied by a factor of 4.04.04.0)

1.3 Transport in cells Questions

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