A student investigated the effect of different concentrations of mannitol solution on the mass of turnip cylinders. The table below shows the results of the investigation after the cylinders were left in the solutions for 45 minutes.
| Cylinder | Concentration of mannitol solution (mol/dm3\text{mol/dm}^3mol/dm3) | Mass at start (g\text{g}g) | Mass after 45 minutes (g\text{g}g) | Change in mass (g\text{g}g) | Percentage (%) change in mass |
|---|---|---|---|---|---|
| A | 0.0 | 3.420 | 3.711 | +0.291 | +8.5 |
| B | 0.1 | 3.550 | 3.692 | +0.142 | +4.0 |
| C | 0.2 | 3.600 | 3.492 | -0.108 | -3.0 |
| D | 0.3 | 3.480 | 3.202 | -0.278 | -8.0 |
| E | 0.4 | 3.580 | 3.136 | -0.444 | YYY |
Based on the measurements in the table, what was the resolution of the balance used?
Calculate the value of YYY to 111 decimal place. Use the formula:
Percentage change in mass=change in massmass at start×100 \text{Percentage change in mass} = \frac{\text{change in mass}}{\text{mass at start}} \times 100 Percentage change in mass=mass at startchange in mass×100Estimate the concentration of mannitol solution (in mol/dm3\text{mol/dm}^3mol/dm3) that would result in no change in mass of the turnip cylinders.
30 exam-style questions on AQA GCSE Biology 1.3 Transport in cells, covering 1.3.1 Diffusion, 1.3.2 Osmosis, and 1.3.3 Active transport. Each one has a worked solution and a mark scheme showing where the marks go.