A student investigated the effect of different concentrations of mannitol solution on the mass of turnip cylinders. The table below shows the results of the investigation after the cylinders were left in the solutions for 45 minutes.
| Cylinder | Concentration of mannitol solution (mol/dm3\text{mol/dm}^3mol/dm3) | Mass at start (g\text{g}g) | Mass after 45 minutes (g\text{g}g) | Change in mass (g\text{g}g) | Percentage (%) change in mass |
|---|---|---|---|---|---|
| A | 0.0 | 3.420 | 3.711 | +0.291 | +8.5 |
| B | 0.1 | 3.550 | 3.692 | +0.142 | +4.0 |
| C | 0.2 | 3.600 | 3.492 | -0.108 | -3.0 |
| D | 0.3 | 3.480 | 3.202 | -0.278 | -8.0 |
| E | 0.4 | 3.580 | 3.136 | -0.444 | YYY |
Based on the measurements in the table, what was the resolution of the balance used?
Calculate the value of YYY to 111 decimal place. Use the formula: Percentage change in mass=change in massmass at start×100\text{Percentage change in mass} = \frac{\text{change in mass}}{\text{mass at start}} \times 100Percentage change in mass=mass at startchange in mass×100
Estimate the concentration of mannitol solution (in mol/dm3\text{mol/dm}^3mol/dm3) that would result in no change in mass of the turnip cylinders.
Practise AQA GCSE Biology 1.3 Transport in cells with exam-style questions for Foundation and Higher tier. 39 questions covering 1.3.1 Diffusion, 1.3.2 Osmosis, and 1.3.3 Active transport, matched to the AQA GCSE Biology (8461) specification and written in Paper 1 and Paper 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.