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1.8 E: Trigonometry

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Question 89
a.

Show that the equation 5−tan⁡θcos⁡θ=6cos⁡2θ5 - \tan\theta \cos\theta = 6\cos^2\theta5−tanθcosθ=6cos2θ can be expressed in the form 6sin⁡2θ−sin⁡θ−1=06\sin^2 \theta - \sin \theta - 1 = 06sin2θ−sinθ−1=0

[2]
b.

The diagram shows parts of the curves y=6cos⁡2θy = 6\cos^2\thetay=6cos2θ and y=5−tan⁡θcos⁡θy = 5 - \tan\theta \cos\thetay=5−tanθcosθ, where θ \theta\,θ is in degrees. Solve the inequality 5−tan⁡θcos⁡θ>6cos⁡2θ5 - \tan\theta \cos\theta > 6\cos^2\theta5−tanθcosθ>6cos2θ for 0∘≤θ<360∘0^\circ \leq \theta < 360^\circ0∘≤θ<360∘

[5]

1.8 E: Trigonometry Questions

  1. A Level
  2. /Maths
  3. /1.8 E: Trigonometry

Practise AQA A Level Maths 1.8 E: Trigonometry with exam-style questions for A Level Maths. 239 questions covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context, matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.

Question bank