Show that the equation
6cos2x=4−sinx 6\cos^2 x = 4 - \sin x 6cos2x=4−sinxCan be written in the form
6sin2x−sinx−2=0 6\sin^2 x - \sin x - 2 = 0 6sin2x−sinx−2=0Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation,
6cos2x=4−sinx 6\cos^2 x = 4 - \sin x 6cos2x=4−sinxGive your answers to one decimal place where appropriate.
Practise AQA A Level Maths 1.8 E: Trigonometry with exam-style questions for A Level Maths. 239 questions covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context, matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.
