Show that the equation
3cosθ−2=5sinθtanθ 3\cos \theta - 2 = 5 \sin \theta \tan \theta 3cosθ−2=5sinθtanθcan be written in the form
8cos2θ−2cosθ−5=0 8\cos^2 \theta - 2\cos \theta - 5 = 0 8cos2θ−2cosθ−5=0Hence solve, for 0≤x<π0 \le x < \pi0≤x<π,
3cos2x−2=5sin2xtan2x 3\cos 2x - 2 = 5 \sin 2x \tan 2x 3cos2x−2=5sin2xtan2xgiving your answers, where appropriate, to 2 decimal places.
Practise AQA A Level Maths 1.8 E: Trigonometry with exam-style questions for A Level Maths. 239 questions covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context, matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.