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1.8 E: Trigonometry

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Question 30
a.

Show that the equation 6cos⁡2x=4−sin⁡x6\cos^2 x = 4 - \sin x6cos2x=4−sinx can be written in the form 6sin⁡2x−sin⁡x−2=06\sin^2 x - \sin x - 2 = 06sin2x−sinx−2=0

[3]
b.

Hence solve, for 0°⩽x<360°0° \leqslant x < 360°0°⩽x<360°, the equation 6cos⁡2x=4−sin⁡x6\cos^2 x = 4 - \sin x6cos2x=4−sinx, giving your answers to 1 decimal place where appropriate.

[5]
Markscheme

1.8 E: Trigonometry Questions

  1. A Level
  2. /Maths
  3. /1.8 E: Trigonometry

317 exam-style questions on AQA A Level Maths 1.8 E: Trigonometry, covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context. Each one has a worked solution and a mark scheme showing where the marks go.

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