In a precision laser alignment system, the deviation ratio DDD for a small angle of incidence θ\thetaθ (measured in radians, where θ≠0\theta \neq 0θ=0) is modeled by the function:
D(θ)=3θsin(4θ)1−cos(5θ) D(\theta) = \frac{3\theta \sin(4\theta)}{1 - \cos(5\theta)} D(θ)=1−cos(5θ)3θsin(4θ)Using small angle approximations, show that for small values of θ\thetaθ, D(θ)≈KD(\theta) \approx KD(θ)≈K where KKK is a constant to be determined.
317 exam-style questions on AQA A Level Maths 1.8 E: Trigonometry, covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context. Each one has a worked solution and a mark scheme showing where the marks go.