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1.8 E: Trigonometry

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Question 14
a.

Prove that

tan⁡ϕ+cot⁡ϕ≡2csc⁡2ϕ \tan \phi + \cot \phi \equiv 2 \csc 2\phi tanϕ+cotϕ≡2csc2ϕ

for ϕ≠nπ2,n∈Z\phi \neq \frac{n\pi}{2}, n \in \mathbb{Z}ϕ=2nπ​,n∈Z.

[3]
b.

Using the identity in part (a), or otherwise, prove that

cot⁡2ϕ−tan⁡2ϕ≡4cot⁡2ϕcsc⁡2ϕ \cot^2 \phi - \tan^2 \phi \equiv 4 \cot 2\phi \csc 2\phi cot2ϕ−tan2ϕ≡4cot2ϕcsc2ϕ

for ϕ≠nπ2,n∈Z\phi \neq \frac{n\pi}{2}, n \in \mathbb{Z}ϕ=2nπ​,n∈Z.

[3]
c.

Hence solve, for −π2<α<π2-\frac{\pi}{2} < \alpha < \frac{\pi}{2}−2π​<α<2π​,

4cot⁡2αcsc⁡2α=3tan⁡2α+1 4 \cot 2\alpha \csc 2\alpha = 3 \tan^2 \alpha + 1 4cot2αcsc2α=3tan2α+1

giving your answers to 2 decimal places.

[4]
Markscheme

1.8 E: Trigonometry Questions

  1. A Level
  2. /Maths
  3. /1.8 E: Trigonometry

317 exam-style questions on AQA A Level Maths 1.8 E: Trigonometry, covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank